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What is the pH of a 0.233m solution of aniline hydrochloride?

What is the pH of a 0.233m solution of aniline hydrochloride?
Fernando Answered Mar 31 2022

Ka = 2.40 X 10^(-5) for aniline hydrochloride.

Assuming you know the dissociation reaction.

Ka = [H+][C6H5NH3+]/[C6H5NH2] = x^2/(0.233 -x)

Assume x<< 0.233

Ka = x^2/0.233

x = SQRT(0.233Ka) = 0.00236

(x/0.233)100% = 1.01% an error that we will accept.

[H+] = x = 0.00236 M

pH = -log(0.00236) = 2.626
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Aniline hydrochloride
142-04-1
CAS No:142-04-1
 
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