Phosphoryl bromide reaction with benzoic acid

I am trying to find out how $\ce{POBr3}$ reacts with $\ce{-COOH}$ group (benzoic acid to be specific). I found that it performs an elimination reaction with alcohols to give alkenes. I have also seen that keto group was converted to $\ce{-Cl}$ using $\ce{POCl3}.$

But I don't think that $\ce{POCl3}$ will eliminate $\ce{-COOH}$ group — that seems like nonsense. Eliminating using $\ce{-OH}$ from $\ce{-COOH}$ would give me a carbon with five bonds. Exchanging the $\ce{=O}$ from $\ce{-COOH}$ would give me something I have never seen and it doesn't even look good…

So I am sort of out of ideas. I'd appreciate any hint what to do.

So the correct answer (according to my teacher) is that R-COBr is generated from the reaction of POBr3 with R-COOH (benzoic acid)

Well actually @Waylander and @Nilay Ghosh are both correct in a way. To convert carboxylic acids into acyl chloride, $\ce{PCl5}$ is often used as a chlorinating agent , which yields an acyl chloride and $\ce{POCl3}$ (and $\ce{HCl}$) as a by-product.

This $\ce{POBr3}$ (or likewise $\ce{POCl3}$) is essentially a dehydrating agent and is thus used to dehydrate alcohols to alkenes(1)

or brominate(2) (in some cases) to form alkyl bromides.

But this dehydrating capability might also be used on carboxylic acids to convert them into their anhydrides just like $\ce{P4O10}$, though there's no such special mention of the viability of the reaction progress.

But since you're really asking, I think conversion of the acid into its anhydride could be a possible outcome in presence of a dehydrating agent $\ce{POBr3}$.